Calculate the mass percentage composition of the elements in nitric acid. $(H=1,N=14,O_s=16)$

Total molar mass of Nitric acid ($HN{O}_3$)$=1+14+16\times 3=63g/mol$

Mass% of H=$\frac{1}{63}\times 100=1.587$%

Mass% of N=$\frac{14}{63}\times 100=22.22$%

Mass% of O=$\frac{48}{63}\times 100=76.19$%