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Question

Calculate the mean deviation about the mean of following frequency distribution:
Class Interval 0-4 4-8 8-12 12-16 16-20
Freq. 4 6 8 5 2

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Solution

Class Interval fi xi fixi
0-4 4 2 8
4-8 6 6 36
8-12 8 10 80
12-16 5 14 70
16-20 2 18 36
Total fi=25 fixi=230

Mean (¯¯¯x)=fixifi=23025=9.2


¯¯¯x=9.2
Class Interval fi xi fixi di=xi¯¯¯x fidi
0-4 4 2 8 7.2 28.8
4-8 6 6 36 3.2 19.2
8-12 8 10 80 0.8 6.4
12-16 5 14 70 4.8 24.0
16-20 2 18 36 8.8 17.6
Total fi=25 fixi=230 fidi=96

Mean deviation =fidifi=9625=3.84

Hence, required mean deviation about mean = 3.84

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