Calculate the Molecular Mass of $Sucrose (Table Sugar) C_{12} H_{22} O_{11}$ .

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Solution

The Atomic Mass of $Carbon (C)$ = $12$ .
The Atomic Mass of $Hydrogen (H)$ = $1$ .
The Atomic Mass of $Oxygen (O)$ = $16$ .
Molecular Mass of $Sucrose (Table Sugar) C_{12} H_{22} O_{11}$ = $12 \times$ (The Atomic Mass of $Carbon (C)$ ) $+$ $22 \times$ (The Atomic Mass of $Hydrogen (H)$ ) $+$ $11 \times$ (The Atomic Mass of $Oxygen (O)$ ).
Molecular Mass of $Sucrose (Table Sugar) C_{12} H_{22} O_{11}$ = $12 \times 12 + 22 \times 1 + 11 \times 16$ .
Hence, Molecular Mass of $Sucrose (Table Sugar) C_{12} H_{22} O_{11}$ ) = $342 g / mol$ .

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