Calculate the molecular mass of $N{H}_3$ molecule in grams.

The correct option is C $2.82\times {10}^{-23}$ g
The atomic mass of ($N$) = 14 u, $\left(H\right)=1u$
So, the molecular mass of $N{H}_3$
$=14+1\times 3=17$ u
$=\frac{17}{6.022\times {10}^{-23}}$ g
$=2.82\times {10}^{-23}$ g