Calculate the number of atoms in $10\text{g}$ of chlorine with that of $10\text{g}$of nitrogen.

Step 1: Given information

• $10\text{g}$ of chlorine$\left(\mathrm{Cl}\right)$
• $10\text{g}$of nitrogen$\left(\mathrm{N}\right)$

Step 2: Molecular weight of nitrogen, and chlorine

The molecular weight of chlorine is $35.5\text{g}$.

The molecular weight of nitrogen is $\text{14 g}$.

Step 3: Calculation of number of atoms of chlorine $\left(\mathrm{Cl}\right)$

$35.5\text{g}$ of chlorine contains $6.022\times {10}^{23}$ molecules.

$10\text{g}$ of chlorine contains $\frac{6.022\times {10}^{23}}{\text{35.5}}\times 10{\text{=1.7×10}}^{23}\text{atoms}$

Step 4: Calculation of number of atoms of nitrogen $\left(\text{N}\right)$

$\text{14 g}$ of nitrogen contains $6.022\times {10}^{23}$ molecules.

$10\text{g}$ of nitrogen contains $\frac{6.022\times {10}^{23}}{\text{14}}\times 10\text{=4.3}\times {10}^{23}\text{atoms}$

Hence, the number of atoms in $10\text{g}$ of chlorine is $1.7\times {10}^{23}$ atoms, and in $10\text{g}$of nitrogen, it is $4.3\times {10}^{23}\text{atoms}$.