Calculate the number of oxygen atoms in 0.10 mole of ${Na}_{2}C{O}_3.10H_{2}0$

Step 1:

From the formula, we can say that,

1 mol of Na₂CO₃.10H₂O contains 10+3 = 13 moles O atoms

we have 0.1 moles of Na₂CO₃.10H₂O

So, we will have 13 x 0.1 = 1.3mol O atoms

Step 2:

Since, 1 mole O atoms = 6.022 x 10²³atoms

1.3 mol O atoms = 1.3 x 6.022 x 10²³ = 0.78 x 10²⁴ O atoms.

Hence, the number of oxygen atoms in 0.10 mole of ${Na}_{2}C{O}_3.10H_{2}O$ are $0.78\times {10}^{24}$