Calculate the number of particles in 46 g of sodium atoms.

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Solution

We know that,
One mole of Sodium= $6.022 \times 10^{23} particles$
Number of moles = $\frac{Given mass}{Molar mass}$
Number of moles of Sodium = $\frac{46}{23}$ = 2 moles
So, 2 moles of Sodium atom contains $6.022 \times 10^{23} \times 2$ = $12.044 \times 10^{23}$ particles.

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