Calculate the number of polyatomic ions which will use brackets when they are used- -160-One - OH- two - NH-4- three - CO-3-one - OCl- two - OH- one - PO-4- -160-one - SO-4- 3- 2- 4- 1-

The correct option is A 3 More than one poly atomic ions are written in #160;brackets so there are three polyatomic ions which are more than one. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Polyatomic Ions-Formula Writing

Calculate the...

Question

Calculate the number of polyatomic ions which will use brackets when they are used.
One $O H$ , two $N H_{4}$ , three $C O_{3}$ ,one $O C l$ , two $O H$ , one $P O_{4}$ , one $S O_{4}$

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

N H_{4}^{+}, N a^{+}, C l^{-}, H^{+}, P O_{4}^{3 -}, N O_{3}^{-}, O H^{-}, O_{2}^{-}

Which of these is a polyatomic ion?

${S O}_{4}^{- 2}$ , ${N O}_{3}^{- 1}$ , ${C O}_{3}^{- 2}$

Which of these is a polyatomic ion?

${S O}_{4}^{- 2}$ , ${N O}_{3}^{- 1}$ , ${C O}_{3}^{- 2}$

A l (O H)_{3}

Z n (O H)_{2}

8.5 \times 10^{- 23}

1.8 \times 10^{- 14}

A l^{3 +}

Z n^{2 +}

N H_{4} O H

S O_{4}

C O_{3}

O H

C r_{2} O_{7}

Join BYJU'S Learning Program