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Question

Calculate the number of water molecule present in one drop of water which weighs 0.18g.

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Solution

One mole of water weighs 18 g.

18 g of water contains 6.023 × 1023 water molecules.

∴ 0.18 g of water contains = 6.02 X 1023 18 ×0.18

= 6.023 × 1021 water molecules


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