Calculate the percentage of nitrogen in ${NH}_{3}$ (Atomic Mass Of N =14 An H=1 Amu).

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Solution

Step 1:- Molecular mass of ${NH}_{3}$
Given the atomic mass of N is 14 amu and that of H is 1 amu
Thus the molecular mass of ${NH}_{3}$ = $14 a m u + (3 \times 1) a m u = 17 a m u$
Step 2:- Percentage composition of N
Percentage composition of N
= $\frac{atomic mass of N \times total numer of N present in the molecule \times 100 %}{total molecular mass of {NH}_{3}}$
= $\frac{14 amu \times 100 %}{17 amu}$
= $82.35 %$
Thus the percentage composition of N in ${NH}_{3}$ is $82.35 %$

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Calculate the percentage of nitrogen in NH3 (Atomic Mass Of N =14 An H=1 Amu).

Calculate the percentage of nitrogen in ${NH}_{3}$ (Atomic Mass Of N =14 An H=1 Amu).