Calculate the pH of the following solutions:

a) 2 g of TlOH dissolved in water to give 2 litre of solution.

b) 0.3 g of Ca(OH)₂ dissolved in water to give 500 mL of solution.

c) 0.3 g of NaOH dissolved in water to give 200 mL of solution.

d) 1mL of 13.6 M HCl is diluted with water to give 1 litre of solution.

1. For 2g of TlOH dissolved in water to give 2 L of solution:

(b) For 0.3 g of Ca(OH)₂ dissolved in water to give 500 mL of solution:

(c) For 0.3 g of NaOH dissolved in water to give 200 mL of solution:

(d) For 1mL of 13.6 M HCl diluted with water to give 1 L of solution:

13.6 × 1 mL = M₂ × 1000 mL

(Before dilution) (After dilution)

13.6 × 10^–3 = M₂ × 1L

M₂ = 1.36 × 10^–2

[H⁺] = 1.36 × 10^–2

pH = – log (1.36 × 10^–2)

= (– .1335 + 2)

= 1.866 ∼ 1.87