Calculate the quantity of heat required to raise the temperature of $5kg$ iron from $303K$ to $343K$. (Specific heat capacity of iron is $460Jk{g}^{-1}{K}^{-1}$)

The correct option is C $92kJ$
Given,
Mass of the iron, $m=5kg$
Specific heat capacity, $c=460Jk{g}^{-1}{K}^{-1}$
Change in temperature, $\theta =343-303=40K$
We know, heat required, $Q=\text{m}\times \text{c}\times \theta$
$=5\times 460\times (343-303)$
$=5\times 460\times 40$
$=92000J$ $=92kJ$