Calculate which of the following calcium nitrate or ammonium sulfate has a higher $%$ of nitrogen.
[ $C a = 40, O = 16, S = 32, N = 14$ ]

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Solution

As we know that,
$percentage by weight = \frac{weight}{total weight} \times 100$
Therefore,
(a)percentage by weight of $N$ in calcium nitrate $(C a {(N O_{3})}_{2})$ -
Molecular weight of nitrogen $= 14 g$
Weight of nitrogen in $C a {(N O_{3})}_{2} = 2 \times 14 g = 28 g$
Weight of $C a {(N O_{3})}_{2} = 164 g$
$∴$ percentage by weight $= \frac{28}{164} \times 100 = 17.073 %$
(b)percentage by weight of $N$ in ammonium sulphate $({(N H_{4})}_{2} S O_{4})$ -
Weight of nitrogen $= 14 g$
Weight of nitrogen in $({(N H_{4})}_{2} S O_{4}) = 2 \times 14 = 28 g$
Weight of $({(N H_{4})}_{2} S O_{4}) = 132 g$
$∴$ percentage by weight $= \frac{28}{132} \times 100 = 21.21 %$
Hence the percentage of nitrogen in ammonium sulphate is higher than that in calcium nitrate.

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Calculate which of the following calcium nitrate or ammonium sulfate has a higher % of nitrogen.[Ca=40, O=16, S=32, N=14]

Calculate which of the following calcium nitrate or ammonium sulfate has a higher $%$ of nitrogen.
[ $C a = 40, O = 16, S = 32, N = 14$ ]