Check if ${119}^2-{111}^2$ is a prime number or composite number.

${119}^2-{111}^2$

$\Rightarrow$ using $a^2-b^2=(a+b)(a-b)$

$\Rightarrow {119}^2-{111}^2=(119+111)(119-111)$

$=230\left(8\right).$

Since, the number has more than two factor other than $1$ and the number itself, it is composite number.

Hence, the answer is $230\left(8\right).$