Colored light is an incident on a prism- If the refractive index for given color of light is -3 and the angle of the prism is 60- the angle of minimum deviation is -

Step 1: Given data and formula usedGiven:Prism angle ∠ A=60°Refractive index μ =√(3)Formula used:μ =sin(A+δ/2)/sin(A/2)Step 2: Calculation for the angle of devi ...

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Byju's Answer

Standard XIII

Physics

Minimum Deviation

Colored light...

Question

Colored light is an incident on a prism. If the refractive index for given color of light is $\sqrt{3}$ and the angle of the prism is $60 °$ , the angle of minimum deviation is _________.

$60 °$

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$30 °$

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$45 °$

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$15 °$

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Solution

The correct option is A
$60 °$

Step 1: Given data and formula used
Given:
Prism angle $∠ A = 60 °$
Refractive index $μ = \sqrt{3}$
Formula used:
$μ = \frac{\sin (\frac{A + δ}{2})}{\sin (\frac{A}{2})}$
Step 2: Calculation for the angle of deviation $δ$
On putting given value in formula used
$\sqrt{3} = \frac{\sin (\frac{60 + δ}{2})}{\sin (\frac{60}{2})} = \frac{\sin (\frac{60 + δ}{2})}{\sin (30)} \sqrt{3} \times \frac{1}{2} = \sin (\frac{60 + δ}{2}) \frac{60 + δ}{2} = 60 ° δ = 60 °$
Hence, the correct option is (a).

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