Complete and balance the equation

${\mathrm{ZnCO}}_3+\mathrm{HCl}\to$

Step 1: When Zinc carbonate $\left({\mathrm{ZnCO}}_3\right)$ reacts with Hydrochloric acid $\left(\mathrm{HCl}\right)$ then it gives Zinc chloride$\left({\mathrm{ZnCl}}_2\right)$, water$\left({\mathrm{H}}_2\mathrm{O}\right)$, and carbon dioxide $\left({\mathrm{CO}}_2\right)$as a gas.

${\mathrm{ZnCO}}_3+\mathrm{HCl}\to {\mathrm{ZnCl}}_2+{\mathrm{H}}_2\mathrm{O}+{\mathrm{CO}}_2$

Step 2: Balancing the given chemical equation step by step as:

1. Count the number of atoms in both the reactant and product sides.

Reactant	Product
Zn- 1	Zn - 1
C - 1	C - 1
O - 3	O - 3
H - 1	H - 2
Cl - 1	Cl - 2

Here, Oxygen, Carbon, and Zinc atoms are balanced but Chlorine and Hydrogen atoms are not balanced on both sides.

2: Multiply $\mathrm{HCl}$ by 2 on the reactant side to balance Chlorine on both sides.

${\mathrm{ZnCO}}_3+2\mathrm{HCl}\to {\mathrm{ZnCl}}_2+{\mathrm{H}}_2\mathrm{O}+{\mathrm{CO}}_2$

3: Count the number of atoms in both the reactant and product sides.

Reactant	Product
Zn- 1	Zn - 1
C - 1	C - 1
O - 3	O - 3
H - 2	H - 2
Cl - 2	Cl - 2

Here, Zinc, Oxygen, Carbon, Hydrogen, and Chlorine atoms are balanced on both sides. Thus, the equation is balanced now.

Step 3: The balanced chemical equation is:

${\mathrm{ZnCO}}_3+2\mathrm{HCl}\to {\mathrm{ZnCl}}_2+{\mathrm{H}}_2\mathrm{O}+{\mathrm{CO}}_2$