Complete and balance the following reaction :
$C_{2} H_{5} N H_{2} + H C l ⟶$

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Solution

$C_{2} H_{5} N H_{2} + H C l \to C_{2} H_{5} N H_{3}^{+} C l^{-}$
When ethyl amine reacts with HCl, it forms ethyl ammonium chloride as a product.

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