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Question

Compute :
(i) 30!28! (ii) 11!10!9!
(iii) L.C.M. (6!,7!,8!)

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Solution

(i) We have
30!28!=30×29×28!28!
= 30×29
= 870
Hence, 30!28!=870
(ii) We have,
11!10!9!=11×10×9110×9!9!
= 9!×10[111]9!
= 10×10
= 100
Hence, 11!10!9!=100
(iii) We have,
8!=8×7×6×5×4×3×2×17!=7×6×5×4×3×2×1
and 6!=6×5×4×3×2×1
L.C.M. (6!,7!,8!)= 8!


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