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Question

Consider a configuration of n identical units, each consisting of three layers. The first layer is a column of air of height h=13 cm, and the second and third layers are of equal thickness d=312cm, and refractive indices μ1=32 and μ2=3, , respectively. A light source O is placed on the top of the first unit, as shown in the figure. A ray of light from O is incident on the second layer of the first unit at an
angle of θ=60
to the normal. For a specific value of n, the ray of light emerges from the bottom of the configuration at a distance l=83cm, as shown in the figure. The value of n is


A
4
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B
4.0
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C
4.00
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Solution

\( 8 / \sqrt{3} \)
For the first layer,
X1h=tan60
X1=htan60=133=13
Now for the total unit consisting of three layersx=x1+x2+x3x=13+312tan45+312tan30
x=13+312+31213x=2+(31)3+3123x=2+33+3123x=423x=23
Given n(x)=83; n(23)=83;n=4

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