Consider the frequency distribution of the heights of 60 students of a class- - Height-in-cm- amp-No-of-Students amp-Cumulative-Frequency- 150-155 amp-16 amp-16- 155-160 amp-12 amp-28- 160-165 amp-9 amp-37- 165-170 amp-7 amp-44- 170-175 amp-10 amp-54- 175-180 amp-6 amp-60- - The sum of the lower limit of the modal class and the upper limit of the median class is - -a- 310- -b- 315- -c- 320- - -d- 330

Modal class = 150 155 So, lower limit of modal class is 150. Total (n) = 60 n/2= 30 Median class = 160 165 So, upper limit of median class = 165 Sum of the low ...

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Standard X

Mathematics

Class Interval

Consider the ...

Question

Consider the frequency distribution of the heights of 60 students of a class:

$\begin{matrix} H e i g h t (i n c m) & N o . o f . S t u d e n t s & C u m u l a t i v e F r e q u e n c y 150 - 155 & 16 & 16 155 - 160 & 12 & 28 160 - 165 & 9 & 37 165 - 170 & 7 & 44 170 - 175 & 10 & 54 175 - 180 & 6 & 60 \end{matrix}$

The sum of the lower limit of the modal class and the upper limit of the median class is :

(a) 310 (b) 315 (c) 320 (d) 330

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Solution

Modal class = 150-155
So, lower limit of modal class is 150.
Total (n) = 60
$\frac{n}{2}$ = 30
Median class = 160-165
So, upper limit of median class = 165
Sum of the lower limit of the modal class and upper limit of the median class = 150 + 165 = 315
Hence, correct option is (b).

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Similar questions

Q. Find the sum of lower limit of the modal class and upper limit of modal class from the following frequency distribution table for the given data:

Class	Frequency
$10 - 20$	$1$
$20 - 30$	$3$
$30 - 40$	$5$
$40 - 50$	$9$
$50 - 60$	$7$
$60 - 70$	$3$

Class	$65 - 85$	$85 - 105$	$105 - 125$	$125 - 145$	$145 - 165$	$165 - 185$	$185 - 205$
Frequency	$4$	$15$	$3$	$20$	$14$	$7$	$14$

Let us find the difference between upper class limit in median class and lower class limit of modal class of the frequency distribution table.

Q. For the distribution :

Marks	Number of students
Below 5	10
Below 10	25
Below 15	37
Below 20	57
Below 25	66

the sum of the lower limits of the median class and the modal class is:

Q. Let m be the mid-point be the upper class limit of a continuous frequency distribution The lower class limit of the class is

For the following distribution the difference in the upper limit of median and modal class is

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Modal class = 150-155 So, lower limit of modal class is 150. Total (n) = 60 n2= 30 Median class = 160-165 So, upper limit of median class = 165 Sum of the lower limit of the modal class and upper limit of the median class = 150 + 165 = 315 Hence, correct option is (b).

Modal class = 150-155
So, lower limit of modal class is 150.
Total (n) = 60
$\frac{n}{2}$ = 30
Median class = 160-165
So, upper limit of median class = 165
Sum of the lower limit of the modal class and upper limit of the median class = 150 + 165 = 315
Hence, correct option is (b).