Consider the nitration of benzene using mixed conc. $H_{2} S O_{4}$ and $H N O_{3}$ . If a large amount of $K H S O_{4}$ is added to the mixture, the rate of nitration will be:

faster

No worries! We‘ve got your back. Try BYJU‘S free classes today!

slower

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

unchanged

No worries! We‘ve got your back. Try BYJU‘S free classes today!

doubled

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B slower
During nitration of benzene with a mixture of nitric acid and sulphuric acid, when large amount of $K H S O_{4}$ is added, the rate of nitration will be slower. Sulphuric acid helps in the formation of electrophile $^{+} N O_{2}$ ion.

$H O N O_{2} + 2 H_{2} S O_{4} ⇌ 2 [H S O_{4}]^{-} + H_{3} O^{+} +^{+} N O_{2}$

When large amount of $K H S O_{4}$ is added, it will provide $H S O_{4}^{-}$ (common ion) which will decreases the concentration of $N O_{2}^{+} .$

Suggest Corrections

Similar questions

Consider the nitration of benzene using mixed conc. $H_{2} S O_{4}$ and $H N O_{3}$ . If a large amount of $K H S O_{4}$ is added to the mixture, the rate of nitration will be:

Q. In the nitration of benzene using a mixture of conc.

H_{2} S O_{4}

and conc.

H N O_{3}

, the species which initiates the reaction is _________.

Q. In the nitration of benzene with a mixture of conc.

H N O_{3}

adn conc.

H_{2} S O_{4}

, the electrophile involved is:

Q. Nitrobenzene can be prepared from benzene by using a mixture of conc.

H N O_{3}

and conc.

H_{2} S O_{4}

. In the nitrating mixture,

H N O_{3}

acts as:

In the nitration of benzene with a mixture of conc $H N O_{3}$ and conc $H_{2} S O_{4}$ , the active species involved are

Join BYJU'S Learning Program

Consider the nitration of benzene using mixed conc. H2SO4 and HNO3. If a large amount of KHSO4 is added to the mixture, the rate of nitration will be:

Consider the nitration of benzene using mixed conc. $H_{2} S O_{4}$ and $H N O_{3}$ . If a large amount of $K H S O_{4}$ is added to the mixture, the rate of nitration will be: