Construct a quadrilateral PQRS in which PQ = 6 cm, QR = 5.6 cm, RS = 2.7 cm, ∠Q = 45° and ∠R = 90°.

Steps of construction:
Step 1: Draw QR= $5.6cm$
Step 2: Make $\angle Q={45}^{\circ }\mathrm{and}\angle R={90}^{\circ }$
Step 3: With Q as the centre, draw an arc of $6cm$. Name that point as P.
Step 4: With R as the centre, draw an arc of $2.7cm$. Name that point as S.
Step 6: Join P and S.
Then, $PQRS$ is the required quadrilateral.