Copper crystallises in F.C.C. with a unit cell length of 361 pm. What is the radius of copper atom?

108 pm

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127 pm

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157 pm

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181 pm

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Solution

The correct option is B 127 pm
For, FCC, $\sqrt{2} a$ = 4r(the atoms touches each other along the face diagonal)
$r = \frac{\sqrt{2} a}{4} = \frac{\sqrt{2} \times 361}{4} = 127 p m$

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