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Question

Correct curve of potential (V) versus distance (r) from centre of two charged spherical shells is


A
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B
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C
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D
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Solution

The correct option is C
For given charged spherical shells

For r<R:

V=kqRk(2q)2R=0

For R<r<2R:

V=kqrk(2q)2R

V=kqrkqR
=ve [for r>R]

Also, V decreases as r increases.

For r>2R:

V=kqrk(2q)r=ve

With increase in r, V decreases in magnitude as is evident from the graph.

Based on these observations, option (a) is correct.
Why this question ?
Concept- If A1B then if B is increases then A will decrease.

But if A1B, then if B is increases then A will also increase as negative integer with less magnitude is greater.


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