David is observing his image in a plane mirror. The distance between the mirror and his image is 4 m. If he moves 1 m towards the mirror, then the distance between David and his image will be:

3 m

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5 m

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6 m

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8 m

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Solution

The correct option is C 6 m

In the case of a plane mirror, the distance between the object and the mirror (d1) is same as the distance between image and mirror (d2).

Distance between the mirror and David’s image, d₂ $=$ 4 m

Therefore, d₁ = d₂

=

4 m

If David moves 1 m towards the mirror, then d₁ $=$ 4 − 1 $=$ 3m Again, d₁ = d₂ $=$ 3 m Therefore, the distance between David and his image is d₁ + d₂ $=$ 3 + 3 $=$ 6 m

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Similar questions

David is observing his image in a plane mirror. The distance between the mirror and his image is 4 m. If he moves 1 m towards the mirror, then the distance between David and his image will be

(i) 3 m

(ii) 5 m

(iii) 6 m

(iv) 8 m

Question 12
David is observing his image in a plane mirror. The distance between the mirror and his image is 4 m. If he moves 1 m towards the mirror, then the distance between David and his image will be
(i) 3 m
(ii) 5 m
(iii) 6 m
(iv) 8 m

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