Define the dispersive power of an optical medium. Refractive indices for violet, yellow and red colours of light are respectively $1.632, 1.620, 1.613$ for flint glass. Find the dispersive power of the material of flint glass.

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Solution

Dispersive power of a medium is defined as the ratio of angular dispersion of white light created by that medium to the mean deviation of light.
Given : $n_{v} = 1.632$ $n_{r} = 1.613$ $n_{y} = 1.620$
Dispersive power of medium $w = \frac{n_{v} - n_{r}}{n_{y} - 1}$
$⟹ w = \frac{1.632 - 1.623}{1.620 - 1} = 0.03$

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Define the dispersive power of an optical medium. Refractive indices for violet, yellow and red colours of light are respectively 1.632,1.620,1.613 for flint glass. Find the dispersive power of the material of flint glass.

Dispersive power of a medium is defined as the ratio of angular dispersion of white light created by that medium to the mean deviation of light. Given : nv=1.632 nr=1.613 ny=1.620Dispersive power of medium w=nv−nrny−1⟹ w=1.632−1.6231.620−1=0.03

Define the dispersive power of an optical medium. Refractive indices for violet, yellow and red colours of light are respectively $1.632, 1.620, 1.613$ for flint glass. Find the dispersive power of the material of flint glass.