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Byju's Answer
Standard XII
Physics
2nd Equation of Motion
Derive second...
Question
Derive second and third equation of motion(mathematically
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Solution
L
e
t
t
h
e
d
i
s
tan
c
e
t
r
a
v
e
l
l
e
d
b
y
t
h
e
b
o
d
y
b
e
“
S
”
.
W
e
k
n
o
w
t
h
a
t
D
i
s
tan
c
e
=
A
v
e
r
a
g
e
v
e
l
o
c
i
t
y
×
T
i
m
e
A
l
s
o
,
A
v
e
r
a
g
e
v
e
l
o
c
i
t
y
=
u
+
v
2
∴
D
i
s
tan
c
e
=
u
+
v
2
×
t
.
.
.
.
.
.
.
.
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.
(
1
)
A
g
a
i
n
w
e
k
n
o
w
t
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a
t
v
=
u
+
a
t
s
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b
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t
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t
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t
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g
t
h
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s
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o
f
“
v
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n
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q
.
(
1
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,
w
e
g
e
t
D
i
s
tan
c
e
=
u
+
u
+
a
t
2
×
t
S
=
2
u
t
+
a
t
2
2
S
=
u
t
+
1
2
a
t
2
t
h
i
s
i
s
s
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c
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n
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e
q
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i
o
n
o
f
m
o
t
i
o
n
.
N
o
w
l
e
t
'
s
d
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r
i
v
e
t
h
i
r
d
e
q
a
t
i
o
n
o
f
m
o
t
i
o
n
F
r
o
m
t
h
e
f
i
r
s
t
e
q
u
a
t
i
o
n
o
f
m
o
t
i
o
n
v
=
u
+
a
t
∴
t
=
v
-
u
a
A
v
e
r
a
g
e
v
e
l
o
c
i
t
y
i
s
g
i
v
e
n
a
s
=
v
+
u
2
D
i
s
tan
c
e
=
A
v
e
r
a
g
e
v
e
l
o
c
i
t
y
×
T
i
m
e
S
=
v
+
u
2
×
v
-
u
a
S
=
v
2
-
u
2
2
a
v
2
=
u
2
+
2
a
s
T
h
i
s
i
s
t
h
i
r
d
e
q
u
a
t
i
o
n
o
f
m
o
t
i
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n
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