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Question
Describe with diagram the laboratory method of preparation of ethylene. Write its chemical reaction with the following. Also write the relevant chemical equations:
(i) Baeyer's reagent
(ii) Ozone
(iii) Sulphur monochloride
(iv) Chlorine
(i) Baeyer's reagent
(ii) Ozone
(iii) Sulphur monochloride
(iv) Chlorine
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Solution
The dehydration of ethanol in presence of conc sulphuric acid or phosphoric acid gives ethylene.
CH3−CH2−OHconc.H2SO4−−−−−−−→−H2OCH2=CH2
The reactions of ethylene with:
(i) Baeyer's reagent (cold dilute alkaline KMnO4): CH2=CH2alkaline.KMnO4−−−−−−−−−−→Δ2HCOOH→2CO2+2H2
(ii) Ozone: H2C=CH21)O3−−−−−−→2)Zn/H2O2HCHO
(iii) Sulphur monochloride: 2H2C=CH2+S2Cl2→S(−CH2−CH2−Cl)2 Mustard gas+S
(iv) Chlorine: H2C=CH2+SCl→Cl−CH2−CH2−Cl 1,2-dichloroethane
CH3−CH2−OHconc.H2SO4−−−−−−−→−H2OCH2=CH2
The reactions of ethylene with:
(i) Baeyer's reagent (cold dilute alkaline KMnO4): CH2=CH2alkaline.KMnO4−−−−−−−−−−→Δ2HCOOH→2CO2+2H2
(ii) Ozone: H2C=CH21)O3−−−−−−→2)Zn/H2O2HCHO
(iii) Sulphur monochloride: 2H2C=CH2+S2Cl2→S(−CH2−CH2−Cl)2 Mustard gas+S
(iv) Chlorine: H2C=CH2+SCl→Cl−CH2−CH2−Cl 1,2-dichloroethane
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