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Question

determine the coordinates (x1,y1) of the point P, where the ray intersects the upper surface of the slab-air boundary.

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Solution

Given: μ=[ky32+1]12

k=1.032

Now lets find x-coordinate;

From Snells Law at initial point;

μairsin900=μsinθ

sinθ=1μ

cosθ=  112ky32+1

=ky32μ ...................(1)

cotθ=cosθsinθ=k12.y34 =dydx
dyy34=k12dx

Integrating

y0dyy34=x0k12dx

y=k2x4256

y=x4256

x=4m

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