Determine the oxidation number of Phosphorous in $H_{3} P O_{4}$ .

$+ 5$

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$+ 4$

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$+ 3$

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$+ 2$

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Solution

The correct option is A
$+ 5$

We know that the oxidation number of $H = + 1$ and $O = - 2$ .
Consider the oxidation number of $P$ be $x$

$3 + x + 4 (- 2) = 0$
$\Rightarrow x = + 5$

Thus the oxidation number of phosphorous in $H_{3} P O_{4}$ is $+ 5$ .

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