$\frac{-7}{5}+\left(\frac{2}{-11}+\frac{-13}{25}\right)=\left(\frac{-7}{5}+\frac{2}{-11}\right)+\frac{-13}{25}$
This property is

Evaluate: $1+3+5+7+9+11+13$

Re-arrange suitably and find the sum in each of the following :

(i)$\frac{11}{12}+\frac{-17}{3}+\frac{11}{2}+\frac{-25}{2}$

(ii)$\frac{-6}{7}+\frac{-5}{6}+\frac{-4}{9}+\frac{-15}{7}$

(iii)$\frac{3}{5}+\frac{7}{3}+\frac{9}{5}+\frac{-13}{15}+\frac{-7}{3}$

(iv) $\frac{4}{13}+\frac{-5}{8}+\frac{-8}{13}+\frac{9}{13}$

(v)$\frac{2}{3}+\frac{-4}{5}+\frac{1}{3}+\frac{2}{5}$

(vi) $\frac{1}{8}+\frac{5}{12}+\frac{2}{7}+\frac{7}{12}+\frac{9}{7}+\frac{-5}{16}$

Question 81 (i)

Simplify: $\frac{13}{11}\times \frac{-14}{5}+\frac{13}{11}\times \frac{-7}{5}+\frac{-13}{11}\times \frac{34}{5}$