Divide the following redox reactions into oxidation and reduction half reactions.

(i) $Z n + P b^{2} \to Z n^{2} + P b$

(ii) $Z n + C u^{2 +} \to Z n^{2} + C u$

(iii) $C l_{2} + 2 B r^{-} \to B r_{2} + 2 C l^{-}$

Open in App

Solution

(i)

Oxidation reaction

$Z n \to Z n^{2 +} + 2 e^{-}$

Reduction reaction

$P b^{2 +} + 2 e^{-} \to P b$

(ii)

Oxidation reaction

$Z n \to Z n^{2 +} + 2 e^{-}$

Reduction reaction

$C u^{2 +} + 2 e^{-} \to C u$

(iii)

Oxidation reaction

$2 B r^{-} \to B r_{2} + 2 e^{-}$

Reduction reaction

$C l_{2} + 2 e^{-} \to 2 C l^{-}$

Suggest Corrections

Similar questions

P b^{2} +

Z n^{2}

^{+}

Z n (s) + P b {C l}_{2} (a q) ⟶ P b (s) + Z n {C l}_{2} (a q)

Z n (s) ⟶ {Z n}^{2 +} (a q) + 2 e^{-}

{P b}^{2 +} (a q) + 2 e^{-} ⟶ P b (s)

C u + Z n^{2 +} \to C u^{2 +} + Z n

M g + F e^{2} \to M g^{2 +} + F e

B r_{2} + 2 C l^{-} \to C l_{2} + 2 B r^{-}

F e + C d^{2 +} \to C d + F e^{2 +}

Z n + C u^{2}^{+} \to Z n^{2}^{+} + C u

What is the oxidizing agent in the following redox reaction?

$Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)$

Join BYJU'S Learning Program