Draw triangles with the measures given

below.

(a) In $∆$ABC , l(AB) = 5.5 cm,l(BC) = 4.2 cm, l(AC) = 3.5 cm

(b) In ∆ STU, l(ST) = 7 cm, l(TU) = 4 cm, l(SU) = 5 cm

(c) In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm

(a) In $∆$ABC , l(AB) = 5.5 cm,l(BC) = 4.2 cm, l(AC) = 3.5 cm
Steps of construction
1. Draw a line AB = 5.5 cm
2. With A as centre and 3.5 cm as the radius, draw an arc above the line AB.
3. With B as the centre and 4.2 cm as the radius, draw an arc cutting the previous drawn arc at point C.
4. Join CA and CB.

$∆$ABC is thus the required triangle.

(b) In ∆ STU, l(ST) = 7 cm, l(TU) = 4 cm, l(SU) = 5 cm
Steps of construction
1. Draw a line ST = 7 cm
2. With S as centre and 5 cm as the radius, draw an arc above the line ST.
3. With T as the centre and 4 cm as the radius, draw an arc cutting the previous drawn arc at point U.
4. Join US and UT.

$∆$STU is thus the required triangle.

(c) In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
Steps of construction
1. Draw a line PQ = 6 cm
2. With P as centre and 4.5 cm as the radius, draw an arc above the line PQ.
3. With Q as the centre and 3.8 cm as the radius, draw an arc cutting the previous drawn arc at point R.
4. Join RP and RQ.

$∆$PQR is thus the required triangle.