During illness an 80 Kg man ran n forever of ${102.2}^{o} F$ instead of normal body temperature of ${98.6}^{o} F$ . Assuming that human body is mostly water,how much heat is required to raise his temperature by that amount

100 kcal

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160 kcal

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50 kcal

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92 kcal

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Solution

The correct option is D 160 kcal
Converting Farenhite to celsius:
${102.2}^{\circ} F \to 39^{\circ} C$ and ${98.6}^{\circ} F \to 39^{\circ} C$
Hence $Δ Q = m . s . Δ Q = 80 \times 1000 \times (39 - 37)$
$Q = 16 \times 10^{4} c a l = 160 k c a l .$

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