- E-o- for the half cell - Zn - 2- -Zn- -160-is - -0-76- e-m-f- of the cell- Zn- Zn - 2- - 1M - -160- - - 2 H - - - 1M - -160- - H - 2 - 1 atm - -160- - -0-76 V- -0-76 V- -0-38 V- -0-38 V-

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Nersnt Equation

E^o for the ...

Question

$E^{o}$ for the half cell ${Z n}^{2 +} | Z n$ is $- 0.76$ e.m.f. of the cell
$Z n ∣ ∣ {Z n}^{2 +} (1 M) ∣ ∣ ∣ ∣ 2 H^{+} (1 M) ∣ ∣ H_{2} (1 a t m)$ :

- 0.76 V

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+ 0.76 V

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- 0.38 V

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+ 0.38 V

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Solution

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$E^{0} Z n^{2 +} / Z n = - 0.76 V$ The EMF of the cell

$Z n / Z n^{2 +} (1 M) | | H C l (p H = 2) | H_{2 (1 a t m)}, P t$ is ::

E^{o}

Z n \to Z n^{2 +} + 2 e^{-}; E^{o} = - 0.76 V

F e^{2 +} + 2 e^{-} \to F e; E^{o} = + 0.41 V

F e^{2 +} + Z n \to Z n^{2 +} + F e

E^{o}

Z n ⟶ {Z n}^{2 +} + 2 e^{-}

E^{o} = + 0.76 V

F e ⟶ {F e}^{2 +} + 2 e^{-}

E^{o} = + 0.41 V

{F e}^{2 +} + Z n ⟶ {Z n}^{2 +} + F e

E^{o}

Z n^{2 +} /Zn

- 0.76 V

Zn/Z n^{2 +} (1M) // H^{+} (1M) / H_{2}

Z n ∣ ∣ {Z n}^{2 +} (1 M) ∣ ∣ ∣ ∣ {C u}^{2 +} (1 M) ∣ ∣ C u

E_{{C u}^{2 +} / C u}^{o} = 0.34 V

E_{{z n}^{2 +} / Z n}^{o} = - 0.76 V

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