Each drop of $H_{2} O$ has $0.018$ ml at room temperature. Number of $H_{2} O$ molecules in one drop is :

1 \times 10^{- 3}

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6.02 \times 10^{20}

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22.4 \times 10^{- 3}

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6.02 \times 3 \times 10^{2}

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Solution

The correct option is C $6.02 \times 10^{20}$
Each drop of $H_{2} O$ has $0.018 m l$ at room temperature and one mole of water contains $18$ g and $6.023 \times 10^{23}$ molecules.
Number of $H_{2} O$ molecules in one drop $= 0.018 \times 6.023 \times 10^{23} / 18 = 6.023 \times 10^{20}$ (density of water is 1g/ml).

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Each drop of H2O has 0.018 ml at room temperature. Number of H2O molecules in one drop is :

The correct option is C 6.02×1020Each drop of H2O has 0.018 ml at room temperature and one mole of water contains 18 g and 6.023×1023 molecules.Number of H2O molecules in one drop=0.018×6.023×1023/18=6.023×1020 (density of water is 1g/ml).

Each drop of $H_{2} O$ has $0.018$ ml at room temperature. Number of $H_{2} O$ molecules in one drop is :