You visited us 1 times! Enjoying our articles? Unlock Full Access!

Huygens' Principle

Electronic co...

Question

Electronic configurations of three elements, $A, B$ and $C$ are given below.

$A : 1 s^{2} 2 s^{2} 2 p^{6}$

$B : 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{3}$

$C : 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}$

Stable form of $C$ may be represented by the formula:

C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $C_{2}$

Element Electronic configuration

$C (C l)$ $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}$

Electronic configuration suggests that $‘ C^{'}$ is $C l$ atom.

It is one electron short from the noble gas configuration, so to complete its octet and acquire stability, $C l$ atoms share one electron with each other and form $C l_{2}$ or $C_{2}$ in the given case.

So, the stable form of $‘ C^{'}$ is $C_{2},$ hence, correct option is $(B) .$

Suggest Corrections

Similar questions

1 s^{2} 2 s^{2} 2 p^{6}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{3}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}

1 s^{2} 2 s^{2} 2 p^{6}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{3}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{1}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{5}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {4 s}^{1}

{(I E)}_{1}

{(I E)}_{4}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{1}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program

Element	Electronic configuration
$C (C l)$	$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}$