Elements A, B, and C with atomic numbers z, z + 1, z + 2 form positive ions having an equal number of electrons. Compare and contrast the sizes of the respective ions.

A^{+ 1} > B^{+ 2} > C^{+ 3}

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A^{+ 1} > C^{+ 3} > B^{+ 2}

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B^{+ 2} > A^{+ 1} > C^{+ 3}

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C^{+ 3} > A^{+ 1} > B^{+ 2}

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Solution

The correct option is B $A^{+ 1} > B^{+ 2} > C^{+ 3}$
For iso electronic species the element with more protons has smaller size. Thus $C^{+ 3}$ is smallest and $A^{+ 1}$ is largest. Thus correct order is
$A^{+ 1} > B^{+ 2} > C^{+ 3}$

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