Eleven bags of wheat flour, each marked 10 kg actually contained the following weights (in kg) of flour:

10.05, 10.20, 10.00, 9.75, 10.00, 10.03, 9.95, 10.35, 9.90, 10.00, 10.08

Find the probability that any of these bags chosen at random contains:

(i) more than 10 kg of wheat flour.

(ii) less than 9.5 kg of wheat flour.

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Solution

We have,

The total number of bags = 11

(i) As, the number of bags containing more than 10 kg of wheat flour = 5

So, the probability of choosing a bag containing more than 10 kg of wheat flour = $\frac{5}{11}$

(ii) As, the number of bags containing less than 9.5 kg of wheat flour = 0

So, the probability of choosing a bag containing less than 9.5 kg of wheat flour = $\frac{0}{11}$ = 0

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Eleven bags of wheat flour, each marked 5 kg actually contained the following weights of flour (in kg):

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