wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Explain faraday's second law of electrolysis in details.


Open in App
Solution

Faraday's second law of electrolysis

  • Michael Faraday established the second law of electrolysis.
  • It states, "The masses of different ions liberated at the electrodes, when the same amount of electricity is passed through different electrolytes are directly proportional to their chemical equivalent weight."
  • The amount of electricity needed to release one gram-equivalent of any material at any electrode is called a faraday, and it passes through an electrolyte.
  • Faraday's constant is equal to 96485Cmol-1.

Formula of Faraday's second law

  • It follows that the electrochemical equivalent of an element is directly proportional to its equivalent weight.

W1W2=E1E2ZE

  • W1,W2 are the deposited amount of any substance.
  • E1,E2 are the equivalent weights of that substance.
  • Z is the electrochemical equivalent.
  • E is the equivalent weight.

Example

  • The same current is passed through the solutions of sulfuric acid H2SO4, copper sulfate CuSO4, and silver nitrate AgNO3 for the same period of time.
  • Then,

MassofcopperdepositedMassofsilverdeposited=EquivalentmassofcopperEquivalentmassofsilverMassofcopperdepositedMassofhydrogengasliberated=EquivalentmassofcopperEquivalentmassofhydrogengas


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sodium Hydroxide
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon