Explain the formation of sodium ion from sodium atom.

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Solution

Formation of sodium ion from sodium atom:
Sodium atom $(Na)$ has atomic number $11$ . Thus, electronic configuration of sodium atom is $(2, 8, 1)$ .
Sodium atom loses one electron from the outermost shell.
On losing one electron, a positively charged sodium ion $({Na}^{+})$ is formed.
Thus, sodium atom $(Na)$ loses one electron and forms sodium ion $({Na}^{+})$ .

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