Express the following speed in $k m / h r$ :
$270 m i n 12 s e c$

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Solution

STEP 1 : Finding the speed in $m / s$
We know that, $S p e e d = \frac{d i s \tan c e t r a v e l l e d}{t i m e t a k e n}$
Speed $= \frac{270}{12} = 22 \frac{1}{2} m / s$
Speed $= 22 \frac{1}{2} = \frac{22 \times 2 + 1}{2} = \frac{45}{2} m / s$
STEP 2 : Converting the speed from $m / s$ to $k m / h r$ .
We know that, $1 m / s = \frac{18}{5} k m / h r$
$\Rightarrow \frac{45}{2} m / s = \frac{45}{2} \times \frac{18}{5} k m / h r$
$\Rightarrow \frac{45}{2} \times \frac{18}{5} = 9 \times 9 = 81 k m / h r$
Hence, $270 m i n 12 s e c$ can be expressed as $81 k m / h r$ .

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Express the following speed in km/hr:270min12sec

STEP 1 : Finding the speed in m/sWe know that, Speed=distancetravelledtimetakenSpeed =27012=2212m/sSpeed =2212=22×2+12=452m/sSTEP 2 : Converting the speed from m/s to km/hr.We know that, 1m/s=185km/hr⇒452m/s=452×185km/hr⇒452×185=9×9=81km/hrHence, 270min12sec can be expressed as 81km/hr.

Express the following speed in $k m / h r$ :
$270 m i n 12 s e c$