Factorise the expression- ax-2- by-2- bxy - axy nbsp-x - y-ax - by-x - nbsp-y-ax - nbsp-by-x - y-ax - nbsp-by-ax - by-ax - by-

The correct option is A (x + y)(ax + by) The given nbsp;expression ax^2+by^2+bxy+axy, can be rearranged as ax^2 + axy + by^2 + bxy Taking 'ax' common from th ...

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Standard VIII

Mathematics

Factors of Natural Numbers

Factorise the...

Question

Factorise the expression:
$a x^{2} + b y^{2} + b x y + a x y$

$(x + y) (a x + b y)$

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$(x - y) (a x - b y)$

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$(x + y) (a x - b y)$

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$(a x + b y) (a x + b y)$

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Solution

The correct option is A
$(x + y) (a x + b y)$

The given expression
$a x^{2} + b y^{2} + b x y + a x y,$
can be rearranged as
$a x^{2} + a x y + b y^{2} + b x y$
Taking 'ax' common from the first two-terms and 'by' common from the last two-terms, we get
$= a x (x + y) + b y (y + x)$
$= (x + y) (a x + b y)$

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Factorise the expression: ax2+by2+bxy+axy

The correct option is A (x+y)(ax+by) The given expression ax2+by2+bxy+axy, can be rearranged as ax2+axy+by2+bxy Taking 'ax' common from the first two-terms and 'by' common from the last two-terms, we get =ax(x+y)+by(y+x) =(x+y)(ax+by)

Factorise the expression:
$a x^{2} + b y^{2} + b x y + a x y$