Factorize- 9a-2 - 48ab - 64b-2-3a - 8b-2-3a - 8b-2-3a - 4b-2-3a - 8b-2

The correct option is D (3a + 8b)^2⇒ 9a^2 + 48ab + 64b^2 ⇒ 9a^2 + 24ab + 24ab + 64b^2 ⇒ 3a(3a + 8b) 8b(3a + 8b) ⇒ (3a + 8b)(3a + 8b) ⇒ (3a + 8b)^2 ...

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Standard X

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Kashmir

Factorize: 9a...

Question

Factorize: $9 a^{2} + 48 a b + 64 b^{2}$

(3 a + 4 b)^{2}

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(3 a + 8 b)^{2}

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(3 a - 8 b)^{2}

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(- 3 a + 8 b)^{2}

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Solution

The correct option is B $(3 a + 8 b)^{2}$
$\Rightarrow 9 a^{2} + 48 a b + 64 b^{2}$
$\Rightarrow 9 a^{2} + 24 a b + 24 a b + 64 b^{2}$
$\Rightarrow 3 a (3 a + 8 b) - 8 b (3 a + 8 b)$
$\Rightarrow (3 a + 8 b) (3 a + 8 b)$
$\Rightarrow (3 a + 8 b)^{2}$

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Similar questions

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9 a^{2} + 3 a - 8 b - 64 b^{2}

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9 a^{2} + \frac{1}{9 a^{2}} - 2 - 12 a + \frac{4}{3 a}

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Factorize: 9a2+48ab+64b2

The correct option is B (3a+8b)2⇒9a2+48ab+64b2 ⇒9a2+24ab+24ab+64b2 ⇒3a(3a+8b)−8b(3a+8b) ⇒(3a+8b)(3a+8b) ⇒(3a+8b)2

Factorize: $9 a^{2} + 48 a b + 64 b^{2}$

The correct option is B $(3 a + 8 b)^{2}$
$\Rightarrow 9 a^{2} + 48 a b + 64 b^{2}$
$\Rightarrow 9 a^{2} + 24 a b + 24 a b + 64 b^{2}$
$\Rightarrow 3 a (3 a + 8 b) - 8 b (3 a + 8 b)$
$\Rightarrow (3 a + 8 b) (3 a + 8 b)$
$\Rightarrow (3 a + 8 b)^{2}$