Fill in the blanks:

$\left(i\right)-4\times \frac{7}{9}=\frac{7}{9}\times$ ___

$\left(ii\right)\frac{5}{11}\times \frac{-3}{8}=\frac{-3}{8}\times$ ___

$\left(iii\right)\frac{1}{2}\times (\frac{3}{4}+\frac{-5}{12})=\frac{1}{2}\times$ ____ $+(\times )\frac{-5}{12}$

$\left(iv\right)\frac{-4}{5}\times \frac{5}{7}\times$___ $=(\frac{-4}{5}\times \frac{5}{7})\times \frac{-8}{9}$

Evaluate :

$\left(i\right)\frac{3}{7}+\frac{-4}{9}+\frac{-11}{7}+\frac{7}{9}\left(ii\right)\frac{2}{3}+\frac{-4}{5}+\frac{1}{3}+\frac{2}{5}\left(iii\right)\frac{4}{7}+0+\frac{-8}{9}+\frac{-13}{7}+\frac{17}{9}\left(iv\right)\frac{3}{8}+\frac{-5}{12}+\frac{3}{7}+\frac{3}{12}+\frac{-5}{8}+\frac{-2}{7}$

Evaluate : $\left(i\right)\frac{5}{9}+\frac{-7}{6}\left(ii\right)4+\frac{3}{-5}\left(iii\right)\frac{1}{-15}+\frac{5}{-12}\left(iv\right)\frac{5}{9}+\frac{3}{-4}\left(v\right)\frac{-8}{9}+\frac{-5}{12}\left(vi\right)0+\frac{-2}{7}\left(vii\right)\frac{5}{-11}+0\left(viii\right)2+\frac{-3}{5}\left(ix\right)\frac{4}{-9}+1$

Re-arrange suitably and find the sum in each of the following :

(i)$\frac{11}{12}+\frac{-17}{3}+\frac{11}{2}+\frac{-25}{2}$

(ii)$\frac{-6}{7}+\frac{-5}{6}+\frac{-4}{9}+\frac{-15}{7}$

(iii)$\frac{3}{5}+\frac{7}{3}+\frac{9}{5}+\frac{-13}{15}+\frac{-7}{3}$

(iv) $\frac{4}{13}+\frac{-5}{8}+\frac{-8}{13}+\frac{9}{13}$

(v)$\frac{2}{3}+\frac{-4}{5}+\frac{1}{3}+\frac{2}{5}$

(vi) $\frac{1}{8}+\frac{5}{12}+\frac{2}{7}+\frac{7}{12}+\frac{9}{7}+\frac{-5}{16}$