Fill in the blanks using the appropriate words given below :
(Sulphur dioxide, Nitrogen dioxide, Nitric oxide, Sulphuric acid)
(i) Cold, dilute nitric acid reacts with copper to give .
(ii) Hot, concentrated nitric acid reacts with copper to form .

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Solution

(i) Reaction of copper with cold dilute nitric acid is:
$3 C u (s) c o p p e r + 8 H {N O}_{3} (a q) n i t r i c a c i d \to 3 C u {({N O}_{3})}_{2} (a q) c o p p e r n i t r a t e + {4 H}_{2} O (l) w a t e r + 2 N O (g) n i t r i c o x i d e$
Gas evolved is nitric oxide.

(ii) $C u + 4 H N O_{3} \to C u (N O_{3})_{2} + 2 H_{2} O + 2 N O_{2}$
With hot nitric acid Nitrogen dioxide is liberated.

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