Find a point on the x- axis which is equidistant from the points (7, 6) and (-3, 4).

Given points A(7,6) and B(-3,4)
Let the point be P(x,0) [we know that point on x-axis is (x,0)]
So, AP=PB and


Hence, point on x-axis which is equidistant from the points A(7,6) and B(-3,4) is (3,0)