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Question

Find M and Y such that M Y in the addition Y + Y + Y = MY.

A
M = 2, Y = 5
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B
M = 1, Y = 5
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C
M = 5, Y = 1
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D
M = 3, Y = 5
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Solution

The correct option is B M = 1, Y = 5
Here, Y+Y+Y=MY
3Y=10M+Y
2Y=10M
M=Y5
So, Y is divisible by 5.
Divisibility of 5 states that a number is divisible by 5 only when the number ends with zero or 5.
Hence Y = 0 or 5.

If Y = 0
Y + Y + Y = 0 + 0 + 0 = 0
then, M = 0
But itt is given that MY, so Y cannot be equal to 0.

If Y = 5
Y + Y + Y = 5 + 5 + 5 = 15
then, MY = 15
M = 1, Y = 5

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