Find the area of a triangle with sides $3 c m, 4 c m, 5 c m .$

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Solution

This triangle is a right $-$ angled triangle $,$ because $3^{2} + 4^{2} = 5^{2}$
Area of the triangle $= \frac{1}{2} \times 3 \times 4 = 6 c m^{2}$

Hence, this is the answer.

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