Find the breadth and perimeter of the rectangle of area $962c{m}^2$ and length $26cm.$

Step 1: Finding the breadth of the rectangle.

Given Area =$962c{m}^2$and length = $26cm.$

Area of rectangle$=\mathrm{l}\times \mathrm{b}\mathrm{where}\mathrm{l}\mathrm{is}\mathrm{length}\mathrm{and}\mathrm{b}\mathrm{is}\mathrm{the}\mathrm{breadth}$

$\Rightarrow 962=26\times b$

$\Rightarrow$ $b=\frac{962}{26}$

$\Rightarrow$ $b=37cm$

Hence, the breadth of the rectangle is$37cm$

Step 2: Finding the perimeter of the rectangle.

We know that length is $26cm$ and breadth is $37cm$

The perimeter of the rectangle$=2(\mathrm{l}+\mathrm{b})$$\mathrm{where}\mathrm{l}\mathrm{is}\mathrm{length}\mathrm{and}\mathrm{b}\mathrm{is}\mathrm{the}\mathrm{breadth}$

$$\begin{gathered} =2(26+37) \\ =2\left(63\right) \\ =126cm \end{gathered}$$

Hence, the breadth of the rectangle is $37cm$ and the perimeter of the rectangle is $126cm$